The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since
A. the function is exponential.
B. the Laplace transform of integral of exp(at) has finite values only for s > a.
C. the Laplace transform integral of exp(at) has initial values only for s > a.
D. the function exp(at) is piece-wise continuous only for s > a.
Show Answer
Answer: B
Share your understanding of this question with the correct explanation.