Simple 4–20 mA FORMULAS
So I put together a simple visual that keeps the key formulas in one place, using a pressure transmitter example.
4–20 mA FORMULAS
Example in the image:
–> Range: 0 to 10 bar (LRV = 0, URV = 10, span = 10 bar)
…
From PV to mA:
…
% span = (PV – LRV) / span
Output mA = 4 + %span × 16
For PV = 7.5 bar:
% span = (7.5 – 0) / 10 = 0.75 (75%)
Output = 4 + 0.75 × 16 = 16 mA
…
From mA to PV:
…
% span = (mA – 4) / 16
PV = LRV + %span × span
For output = 12 mA:
% span = (12 – 4) / 16 = 0.5 (50%)
PV = 0 + 0.5 × 10 = 5 bar
MORE INFO. HERE: 4-20mA Formulas and Examples | Instrumentation Formulas
The image walks through these steps so you can screenshot it and use it as a quick reference on the job.
Share the image if you like.
#instrumentation #processcontrol #transmitters #industrialautomation #calibration #processengineering #controlsystems #maintenance
