Simple 4–20 mA FORMULAS

Simple 4–20 mA FORMULAS

So I put together a simple visual that keeps the key formulas in one place, using a pressure transmitter example.

4–20 mA FORMULAS

Example in the image:

–> Range: 0 to 10 bar (LRV = 0, URV = 10, span = 10 bar)

From PV to mA:

% span = (PV – LRV) / span

Output mA = 4 + %span × 16

For PV = 7.5 bar:

% span = (7.5 – 0) / 10 = 0.75 (75%)

Output = 4 + 0.75 × 16 = 16 mA


From mA to PV:

% span = (mA – 4) / 16

PV = LRV + %span × span

For output = 12 mA:

% span = (12 – 4) / 16 = 0.5 (50%)

PV = 0 + 0.5 × 10 = 5 bar

MORE INFO. HERE: 4-20mA Formulas and Examples | Instrumentation Formulas

The image walks through these steps so you can screenshot it and use it as a quick reference on the job.

Share the image if you like.

#instrumentation #processcontrol #transmitters #industrialautomation #calibration #processengineering #controlsystems #maintenance

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